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2.0.1
查询为空时,需要加判断,不然拼接sql会报错
这里要加判断是否为空
Collection<String> anntIds = sysAnnouncementSendService.queryByUserId(userId); LambdaQueryWrapper<SysAnnouncement> querySaWrapper = new LambdaQueryWrapper<SysAnnouncement>(); querySaWrapper.eq(SysAnnouncement::getMsgType, CommonConstant.MSG_TYPE_ALL); // 全部人员 querySaWrapper.eq(SysAnnouncement::getDelFlag, CommonConstant.DEL_FLAG_0); // 未删除 querySaWrapper.eq(SysAnnouncement::getSendStatus, CommonConstant.HAS_SEND); //已发布 if (!anntIds.isEmpty()) { querySaWrapper.notIn(SysAnnouncement::getId, anntIds); } List<SysAnnouncement> announcements = sysAnnouncementService.list(querySaWrapper);
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这块已经改了,下个版本更新上去 3Q
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版本号:
2.0.1
问题描述:
查询为空时,需要加判断,不然拼接sql会报错
截图&代码:
这里要加判断是否为空
The text was updated successfully, but these errors were encountered: