[js] 第72天写一个字符串重复的repeat函数 #511

haizhilin2013 · 2019-06-26T20:35:12Z

第72天写一个字符串重复的repeat函数

AnsonZnl · 2019-06-27T02:28:59Z

var str='abcd';
function repeat(str,n){
    var type = typeof(str) === 'string';
    var result='';
    if(!type){
        return 'Type Error';
    }
    for(var i=0;i<n;i++){
        result += str;
    }
    return result;
}
repeat(str,2);//'abcdabcd'

haizhilin2013 · 2019-06-27T02:30:00Z

@AnsonZnl 不错，还有别的方法吗？

AnsonZnl · 2019-06-27T02:53:31Z

@AnsonZnl 不错，还有别的方法吗？

var str='abcd';
function repeat(str,n){
    if((typeof str) === 'string'){
       return (new Array(n+1)).join(str)
    }
    return 'Type Error'
 }
 repeat(str,3)//abcdabcdabcd

百度看到的哈哈

haizhilin2013 · 2019-06-27T03:19:10Z

@AnsonZnl 也不错，还有别的方法吗？

thisisandy · 2019-06-27T03:26:24Z

const repeat = (str, n)=>str.repeat(n)

thisisandy · 2019-06-27T05:08:13Z

const repeat = (str,n)=>str.padEnd(((n+1)*str.length,str)

maoqxxmm · 2019-06-28T03:16:16Z

const repeatStr = (str, num) => {
  return Array(num + 1).fill(str).join('')
}

leehf · 2019-07-05T02:23:49Z

const repeat = (str) => {return typeof(str) === 'string' ?str+str:'type error';}

Konata9 · 2019-07-05T10:10:08Z

const repeatStr = ({str = "", repeat = 1}) => {
  if (!str || repeat === 0) {
    return str;
  }

  return (str += repeatStr({str: str, repeat: (repeat -= 1)}));
};

console.log(repeatStr({str: "abc", repeat: 3}));
console.log(repeatStr({str: "abc_e", repeat: 2}));
console.log(repeatStr({str: "abc||", repeat: 4}));
console.log(repeatStr({str: "a b c_", repeat: 2}));
console.log(repeatStr({str: "_abc_", repeat: 3}));
console.log(repeatStr({str: "_abc_"}));

ahonn · 2019-07-12T05:51:40Z

时间复杂度：O(logN)

const repeat = (str, count) => {
  if (count === 0) {
    return '';
  }
  if (count === 1) {
    return str;
  }

  let result = repeat(str + str, count >> 1)
  if (count & 1) {
    result += str;
  }
  return result;
}

Alonggg · 2019-07-16T09:23:20Z

let a = [...b , ...c].join() b或者c给一个空数组菜鸡前端方法有点偏门不知道对不对

wyx2014 · 2019-07-25T07:46:13Z

const repeat = function (str, count,sumStr='') {
    if(typeof str !=='string'){
        return 'type error';
    }
    sumStr = sumStr + str;
    return count !==1 ? repeat(str,--count,sumStr):sumStr;
}

Vi-jay · 2019-07-31T08:21:55Z

String.prototype.repeat = function (count) {
  let originStr = String(this);
  let thisStr = this;
  for (let i = 1; i < count; i++) {
    thisStr += originStr;
  }
  return thisStr
};
console.log("asd".repeat(2));

woodPeckerAnos · 2019-08-12T03:15:35Z

ES6本身提供了String实例的repeat方法，如果还要手写，一般是考虑兼容性问题，得用旧的语法

function repeat (str, times) {
    if (typeof String.prototype.repeat === 'function') {
      return str.repeat(times)
    } else {
      var arr = new Array(times)
      for (var i = 0; i < times; i++) {
        arr[i] = str
      }
      return arr.join('')
    }
  }

seho-dev · 2019-10-20T12:29:12Z

var str = "123";
var number = 4;

console.log(test4());

function test1() {
return str.repeat(number);
}

function test2() {
return new Array(number + 1).join(str);
}

function test3() {
let result = "";
for (let i = 0; i < number; i++) {
result += str;
}
return result;
}

function test4() {
let arr = new Array(number);
for (let key in arr) {
arr[key] = str;
}
return arr.join("");
}

zhangkuibao · 2020-03-04T03:49:44Z

function repeat(str,n) {
var result = '';
while(n-- > 0){
result += str;
}
return result ;
}

smile-2008 · 2021-01-20T02:10:57Z

@AnsonZnl 不错，还有别的方法吗？

var str='abcd';
function repeat(str,n){
    if((typeof str) === 'string'){
       return (new Array(n+1)).join(str)
    }
    return 'Type Error'
 }
 repeat(str,3)//abcdabcdabcd

百度看到的哈哈

1684838553 · 2021-12-09T08:51:59Z

String.prototype.myRepeat = function(){
    const num = arguments[0]
    const str = this.toString()
    if(typeof num !== 'number'){
        throw new Error('参数要为number类型')
    }
    let result = ''
    if(num === 0){
        result = ''
    } else if( num > 0 && num !== Infinity  ){
        for(let i = 0;i < num ; i++){
            result += str
        }
    } else {
        throw new Error('请输入正确的参数')
    }
    return result
}
const str = 'repeat'
let newStr = str.myRepeat(5)
console.log(newStr)

xiaoqiangz · 2022-06-17T09:20:16Z

function repeat(str, num) {
if (typeof num !="number") {
throw new Error('必须为number类型')
}
let result = ''
if (num > 0 && num < Infinity) {
// for(let i=0; i < num; i++) {
// result += str
// }
result = new Array(num).join(str)
}
return result
}

```
console.log(repeat('res26', 5))
```

haizhilin2013 added the js label Jun 26, 2019

[js] 第72天 写一个字符串重复的repeat函数 #511

[js] 第72天 写一个字符串重复的repeat函数 #511

Comments

haizhilin2013 commented Jun 26, 2019

AnsonZnl commented Jun 27, 2019 • edited Loading Uh oh! There was an error while loading. Please reload this page.

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haizhilin2013 commented Jun 27, 2019

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haizhilin2013 commented Jun 27, 2019

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seho-dev commented Oct 20, 2019

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zhangkuibao commented Mar 4, 2020

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1684838553 commented Dec 9, 2021 • edited Loading Uh oh! There was an error while loading. Please reload this page.

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xiaoqiangz commented Jun 17, 2022

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[js] 第72天写一个字符串重复的repeat函数 #511

[js] 第72天写一个字符串重复的repeat函数 #511

AnsonZnl commented Jun 27, 2019 •

edited

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maoqxxmm commented Jun 28, 2019 •

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Konata9 commented Jul 5, 2019 •

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ahonn commented Jul 12, 2019 •

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woodPeckerAnos commented Aug 12, 2019 •

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1684838553 commented Dec 9, 2021 •

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