[js] 第711天实现一个函数柯里化 #3740

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[js] 第711天实现一个函数柯里化#3740

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第711天实现一个函数柯里化

我也要出题

added

on Mar 26, 2021

function sum(a){
return(b)=>{
return (c)=>{
return a+b+c
}
}
}
console.log(sum(1)(2)(3))

let result=0
const curryScore = function(fn){
let score = []
return function(){
if(arguments.length === 0){
fn.apply(null,score)
}else{
score = score.concat(Array.prototype.slice.call(arguments,0))
}
}
}
const addScore = curryScore(function(){

result = Array.prototype.slice.call(arguments,0).reduce(function(prev,next){
	return prev+next
})

})
addScore(1)
addScore(2)
addScore()
console.log(result)

function add(...args){

return args.reduce((a, b) => a + b)

}

function currying(fn){
// 返回一个函数用于接收参数
let score = []
return function inner(...args){

	//判断 如果调用函数中没有传入参数则 返回结果 否则返回自身
	if(args.length === 0){
		return fn.apply(this,score)
	}else{
		score = [...score,...args]
		return inner
	}
}

}
let addCurry = currying(add)
console.log(addCurry(1)(2)(3)())

const curry = function(fn) {
        const arity = fn.length; // 获取参数个数

        return function $curry(...args) {
            if (args.length === arity) {
                return fn.apply(this, args);
            } else {
                return function(...args2) {
                    return $curry.apply(this, args.concat(args2));
                }
            }
        }
    }

    const test = function(a, b, c) {
        return a + b + c;
    }

    const curriedTest = curry(test);
    const result = curriedTest(1)(2)(3);
    console.log('result:', result); // 6
    
    const result2 = curriedTest(1)(2, 3);
    console.log('result2:', result2); // 6

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