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[js] 第46天 写一个使两个整数进行交换的方法（不能使用临时变量） #175

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haizhilin2013 opened this issue May 31, 2019 · 14 comments
Open

[js] 第46天 写一个使两个整数进行交换的方法（不能使用临时变量） #175

haizhilin2013 opened this issue May 31, 2019 · 14 comments
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@haizhilin2013
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第46天 写一个使两个整数进行交换的方法（不能使用临时变量）
@haizhilin2013 haizhilin2013 added the js JavaScript label May 31, 2019
@xiangshuo1992
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利用运算符优先级和0*
b = a + 0 * (a = b);
利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

@chwech
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chwech commented Jun 3, 2019 

let a = 1, b= 2
[a, b] = [b, a]

@wenyejie
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wenyejie commented Jun 3, 2019

利用运算符优先级和0*
b = a + 0 * (a = b);
利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

我去这种骚操作, 我只知道一个解构.

@myprelude
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  • ES6
let [a,b] = [b,a]
  • ES5
var a = 1,b = 2;
a = b+a;
b = a-b;
a = a-b;

@chenliwen123
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  • ES6
let [a,b] = [b,a]
  • ES5
var a = 1,b = 2;
a = b+a;
b = a-b;
a = a-b;

ES 6 这个 优秀

@seho-dev
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不能使用临时变量的是什么意思求解答

@vincent-yan
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vincent-yan commented Sep 16, 2019 via email

@zxl-lxz
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zxl-lxz commented Mar 31, 2020 •
edited 

let a = 1;
let b = 2;
[a, b] = [b, a];
console.log(a, b); // => 2, 1

@blueRoach
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let a = 1, b = 2
return [a, b] = [b, a]

@Alex-Li2018
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  1. 第一种
let b = 1
let c = 2
let tmp
tmp = b
b = c
c = tmp
  1. 第二种
let a = 1;
let b = 2;
[a, b] = [b, a];

@MrZ2019
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MrZ2019 commented Nov 12, 2020

利用运算符优先级和0*
b = a + 0 * (a = b);
利用执行顺序

a = a + b;
b = a - b;
a = a - b;

异或取值

a ^= b;
b ^= a;
a ^= b;

@OldSixLi
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分享个新鲜的用法

let a = 0;
let b = 1;
a = [b, b = a][0];
console.log(a, b);

@xiaoqiangz
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es6 解构
[a,b] = [b,a]

@wyy-g
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wyy-g commented Sep 19, 2022

ES6解构赋值 [a, b] = [b, a];
ES5 a = a + b;
b = a - b;
a = a - b;

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